X^2+9x=190

Solution for X^2+9x=190 equation:

X^2+9X=190

We move all terms to the left:

X^2+9X-(190)=0

a = 1; b = 9; c = -190;
Δ = b2-4ac
Δ = 92-4·1·(-190)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-29}{2*1}=\frac{-38}{2}
=-19
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+29}{2*1}=\frac{20}{2}
=10
$